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	<title>Comments on: AES Explained</title>
	<atom:link href="http://www.x-n2o.com/aes-explained/feed/" rel="self" type="application/rss+xml" />
	<link>http://www.x-n2o.com/aes-explained/</link>
	<description>Code your own reality</description>
	<lastBuildDate>Fri, 27 Aug 2010 09:01:08 +0000</lastBuildDate>
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		<title>By: CPUs Notebooks mit AES-NI - AES-Hardwarebeschleunigung für TrueCrypt-Verschlüsselung ... ScareWare.de</title>
		<link>http://www.x-n2o.com/aes-explained/comment-page-1/#comment-842</link>
		<dc:creator>CPUs Notebooks mit AES-NI - AES-Hardwarebeschleunigung für TrueCrypt-Verschlüsselung ... ScareWare.de</dc:creator>
		<pubDate>Fri, 27 Aug 2010 09:01:08 +0000</pubDate>
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		<description>[...] AES erklärt, mit C-Schnipseln [...]</description>
		<content:encoded><![CDATA[<p>[...] AES erklärt, mit C-Schnipseln [...]</p>
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	<item>
		<title>By: X-N2O</title>
		<link>http://www.x-n2o.com/aes-explained/comment-page-1/#comment-629</link>
		<dc:creator>X-N2O</dc:creator>
		<pubDate>Fri, 23 Jul 2010 10:03:03 +0000</pubDate>
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		<description>Hello Nathan,

Yes, m(x) is irreducible. It needs to be irreducible, because else the result of the multiplication cannot have a multiplicative inverse. http://en.wikipedia.org/wiki/Modular_multiplicative_inverse states clearly that &quot;The multiplicative inverse of a modulo m exists iff a and m are coprime (i.e., if gcd(a, m) = 1).&quot;

The definition of irreducible polynomials is as follows (fips-197.pdf page 10): &quot;A polynomial is
irreducible if its only divisors are one and itself.&quot; That&#039;s pretty much also the definition of prime numbers.</description>
		<content:encoded><![CDATA[<p>Hello Nathan,</p>
<p>Yes, m(x) is irreducible. It needs to be irreducible, because else the result of the multiplication cannot have a multiplicative inverse. <a href="http://en.wikipedia.org/wiki/Modular_multiplicative_inverse" rel="nofollow">http://en.wikipedia.org/wiki/Modular_multiplicative_inverse</a> states clearly that &#8220;The multiplicative inverse of a modulo m exists iff a and m are coprime (i.e., if gcd(a, m) = 1).&#8221;</p>
<p>The definition of irreducible polynomials is as follows (fips-197.pdf page 10): &#8220;A polynomial is<br />
irreducible if its only divisors are one and itself.&#8221; That&#8217;s pretty much also the definition of prime numbers.</p>
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	<item>
		<title>By: Nathan</title>
		<link>http://www.x-n2o.com/aes-explained/comment-page-1/#comment-627</link>
		<dc:creator>Nathan</dc:creator>
		<pubDate>Fri, 23 Jul 2010 01:34:59 +0000</pubDate>
		<guid isPermaLink="false">http://www.x-n2o.com/?p=165#comment-627</guid>
		<description>Is m(x) irreducible? Would you mind elaborating on the necessity of modulo an irreducible polynomial over finite fields?</description>
		<content:encoded><![CDATA[<p>Is m(x) irreducible? Would you mind elaborating on the necessity of modulo an irreducible polynomial over finite fields?</p>
]]></content:encoded>
	</item>
	<item>
		<title>By: ali farmani</title>
		<link>http://www.x-n2o.com/aes-explained/comment-page-1/#comment-443</link>
		<dc:creator>ali farmani</dc:creator>
		<pubDate>Thu, 20 May 2010 12:15:14 +0000</pubDate>
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		<description>hi
i implement aes algorithm your algorithm is funny and good .</description>
		<content:encoded><![CDATA[<p>hi<br />
i implement aes algorithm your algorithm is funny and good .</p>
]]></content:encoded>
	</item>
	<item>
		<title>By: casperDT</title>
		<link>http://www.x-n2o.com/aes-explained/comment-page-1/#comment-386</link>
		<dc:creator>casperDT</dc:creator>
		<pubDate>Sun, 02 May 2010 10:54:10 +0000</pubDate>
		<guid isPermaLink="false">http://www.x-n2o.com/?p=165#comment-386</guid>
		<description>This article is just PERFECT

thank you, keep going</description>
		<content:encoded><![CDATA[<p>This article is just PERFECT</p>
<p>thank you, keep going</p>
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